(x-1)(x^2-3x+4)=0

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Solution for (x-1)(x^2-3x+4)=0 equation:


Simplifying
(x + -1)(x2 + -3x + 4) = 0

Reorder the terms:
(-1 + x)(x2 + -3x + 4) = 0

Reorder the terms:
(-1 + x)(4 + -3x + x2) = 0

Multiply (-1 + x) * (4 + -3x + x2)
(-1(4 + -3x + x2) + x(4 + -3x + x2)) = 0
((4 * -1 + -3x * -1 + x2 * -1) + x(4 + -3x + x2)) = 0
((-4 + 3x + -1x2) + x(4 + -3x + x2)) = 0
(-4 + 3x + -1x2 + (4 * x + -3x * x + x2 * x)) = 0
(-4 + 3x + -1x2 + (4x + -3x2 + x3)) = 0

Reorder the terms:
(-4 + 3x + 4x + -1x2 + -3x2 + x3) = 0

Combine like terms: 3x + 4x = 7x
(-4 + 7x + -1x2 + -3x2 + x3) = 0

Combine like terms: -1x2 + -3x2 = -4x2
(-4 + 7x + -4x2 + x3) = 0

Solving
-4 + 7x + -4x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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